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(4x)^2=41.531
We move all terms to the left:
(4x)^2-(41.531)=0
We add all the numbers together, and all the variables
4x^2-41.531=0
a = 4; b = 0; c = -41.531;
Δ = b2-4ac
Δ = 02-4·4·(-41.531)
Δ = 664.496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{664.496}}{2*4}=\frac{0-\sqrt{664.496}}{8} =-\frac{\sqrt{}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{664.496}}{2*4}=\frac{0+\sqrt{664.496}}{8} =\frac{\sqrt{}}{8} $
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